Taking a swimming pool in Quanzhou, 

Fujian Province as an example, this paper designs an air-source heat pump system for the pool. 

The designed pool temperature is 27℃, operating at a constant temperature year-round.

Situational understanding and determination of relevant data:

(1) The average annual temperature in this region is 20℃, 

with the average temperature of the hottest month reaching 29℃ 

and the average temperature of the coldest month being 9℃.

Based on this situation, the following data is determined:

Pool water temperature: 27℃.

(2) Initial water temperature: 15℃;

(3) Swimming pool surface wind speed: Based on the local average ground wind speed, 

combined with the pool's environment and geographical location, and referring to standards, 

an estimated value is made: 0.2 m/s.

(4) The pool's surface area is 1250 m², and its water capacity is 2500 t.

Step 1: Calculate Heating Capacity

The initial heating process needs to be completed in 48 hours. The initial water temperature is 15℃, 

and the temperature needs to be heated to 27℃. Therefore, the required power is:

2500 x (27-15) x 1000 (kcal) / (48 x 860) = 727 (kW)

The required heat pump power is: 727 / 5 = 145 (kW)

Since there is still heat loss due to water evaporation and pipework during the heating process,

 this must be taken into account.

Step 2: Calculate the heat dissipation from the pool surface

Calculation Formula:

Qz = αy(Pb―Pq)(0.0174vf+0.0229)(760/B)

α - Heat conversion factor α = 4.1868 kJ/kcal;

y - Latent heat of vaporization of saturated steam at the same temperature as the pool water: 581.9 (kcal/kg);

vf - Wind speed at the pool surface: 0.2 m/s;

pь - Partial pressure of water vapor in saturated air at the same temperature as the pool water: 26.7 mmHg;

Pq - Water vapor pressure of ambient air at the pool: 16 mmHg, the average humidity of a typical pool is 60%;

A - Surface area of the pool water: 1250 m²;

B - Local atmospheric pressure: 760 mmHg. Substituting the values:

Qz = 4.1868 x 581.9 x 1250 x (0.0174 x 0.2 x 0.0229) x (26.7 - 16) x (760/760)

= 859605 (kJ/h)

Step 3: Calculate the heat loss due to conduction from the pool surface, bottom, walls, pipes, and equipment: 

Qe = 20%Qz = 0.2 x 859605 = 171921 (kJ/h)

Step 4: Calculate the total power and associated power.

Heat loss due to heat dissipation from the pool surface and conduction from the water surface, 

bottom, walls, pipes, and equipment: (859605 + 171921) / 3600 = 286 (kW)

Total power = 286 + 727 = 1013 (kW)

COP = 5

Associated power = 1013/5 = 202 (kW)

Conclusion: Using FAP-25 units, the input power of a single unit is 20.35 kW, 

and the heating power of 10 units is 200.35 kW. The heating efficiency COP in the chart is taken as 5.9.

Therefore, the total heating power = 20.35 x 10 x 5.9 - 1182 (kW)

翻译结果

翻译结果

Diagram of an air source heat pump heating system for a swimming pool